Optimal. Leaf size=686 \[ \frac{\left (-5 a^2 b^2 (27 A+4 B)-a^3 (27 A b-84 b B)+6 a^4 (A+2 B)+5 a b^3 (7 A-12 B)+105 A b^4\right ) \cot (c+d x) \sqrt{\frac{b (1-\sec (c+d x))}{a+b}} \sqrt{-\frac{b (\sec (c+d x)+1)}{a-b}} \text{EllipticF}\left (\sin ^{-1}\left (\frac{\sqrt{a+b \sec (c+d x)}}{\sqrt{a+b}}\right ),\frac{a+b}{a-b}\right )}{12 a^4 d \sqrt{a+b} \left (a^2-b^2\right )}-\frac{b \left (-170 a^2 A b^3+33 a^4 A b+104 a^3 b^2 B-12 a^5 B-60 a b^4 B+105 A b^5\right ) \tan (c+d x)}{12 a^4 d \left (a^2-b^2\right )^2 \sqrt{a+b \sec (c+d x)}}-\frac{b \left (27 a^2 A b-12 a^3 B+20 a b^2 B-35 A b^3\right ) \tan (c+d x)}{12 a^3 d \left (a^2-b^2\right ) (a+b \sec (c+d x))^{3/2}}-\frac{\left (-170 a^2 A b^3+33 a^4 A b+104 a^3 b^2 B-12 a^5 B-60 a b^4 B+105 A b^5\right ) \cot (c+d x) \sqrt{\frac{b (1-\sec (c+d x))}{a+b}} \sqrt{-\frac{b (\sec (c+d x)+1)}{a-b}} E\left (\sin ^{-1}\left (\frac{\sqrt{a+b \sec (c+d x)}}{\sqrt{a+b}}\right )|\frac{a+b}{a-b}\right )}{12 a^4 b d (a-b) (a+b)^{3/2}}-\frac{\sqrt{a+b} \left (4 a^2 A-20 a b B+35 A b^2\right ) \cot (c+d x) \sqrt{\frac{b (1-\sec (c+d x))}{a+b}} \sqrt{-\frac{b (\sec (c+d x)+1)}{a-b}} \Pi \left (\frac{a+b}{a};\sin ^{-1}\left (\frac{\sqrt{a+b \sec (c+d x)}}{\sqrt{a+b}}\right )|\frac{a+b}{a-b}\right )}{4 a^5 d}-\frac{(7 A b-4 a B) \sin (c+d x)}{4 a^2 d (a+b \sec (c+d x))^{3/2}}+\frac{A \sin (c+d x) \cos (c+d x)}{2 a d (a+b \sec (c+d x))^{3/2}} \]
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Rubi [A] time = 2.05047, antiderivative size = 686, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 8, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.242, Rules used = {4034, 4104, 4060, 4058, 3921, 3784, 3832, 4004} \[ -\frac{b \left (-170 a^2 A b^3+33 a^4 A b+104 a^3 b^2 B-12 a^5 B-60 a b^4 B+105 A b^5\right ) \tan (c+d x)}{12 a^4 d \left (a^2-b^2\right )^2 \sqrt{a+b \sec (c+d x)}}-\frac{b \left (27 a^2 A b-12 a^3 B+20 a b^2 B-35 A b^3\right ) \tan (c+d x)}{12 a^3 d \left (a^2-b^2\right ) (a+b \sec (c+d x))^{3/2}}+\frac{\left (-5 a^2 b^2 (27 A+4 B)-a^3 (27 A b-84 b B)+6 a^4 (A+2 B)+5 a b^3 (7 A-12 B)+105 A b^4\right ) \cot (c+d x) \sqrt{\frac{b (1-\sec (c+d x))}{a+b}} \sqrt{-\frac{b (\sec (c+d x)+1)}{a-b}} F\left (\sin ^{-1}\left (\frac{\sqrt{a+b \sec (c+d x)}}{\sqrt{a+b}}\right )|\frac{a+b}{a-b}\right )}{12 a^4 d \sqrt{a+b} \left (a^2-b^2\right )}-\frac{\left (-170 a^2 A b^3+33 a^4 A b+104 a^3 b^2 B-12 a^5 B-60 a b^4 B+105 A b^5\right ) \cot (c+d x) \sqrt{\frac{b (1-\sec (c+d x))}{a+b}} \sqrt{-\frac{b (\sec (c+d x)+1)}{a-b}} E\left (\sin ^{-1}\left (\frac{\sqrt{a+b \sec (c+d x)}}{\sqrt{a+b}}\right )|\frac{a+b}{a-b}\right )}{12 a^4 b d (a-b) (a+b)^{3/2}}-\frac{\sqrt{a+b} \left (4 a^2 A-20 a b B+35 A b^2\right ) \cot (c+d x) \sqrt{\frac{b (1-\sec (c+d x))}{a+b}} \sqrt{-\frac{b (\sec (c+d x)+1)}{a-b}} \Pi \left (\frac{a+b}{a};\sin ^{-1}\left (\frac{\sqrt{a+b \sec (c+d x)}}{\sqrt{a+b}}\right )|\frac{a+b}{a-b}\right )}{4 a^5 d}-\frac{(7 A b-4 a B) \sin (c+d x)}{4 a^2 d (a+b \sec (c+d x))^{3/2}}+\frac{A \sin (c+d x) \cos (c+d x)}{2 a d (a+b \sec (c+d x))^{3/2}} \]
Antiderivative was successfully verified.
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Rule 4034
Rule 4104
Rule 4060
Rule 4058
Rule 3921
Rule 3784
Rule 3832
Rule 4004
Rubi steps
\begin{align*} \int \frac{\cos ^2(c+d x) (A+B \sec (c+d x))}{(a+b \sec (c+d x))^{5/2}} \, dx &=\frac{A \cos (c+d x) \sin (c+d x)}{2 a d (a+b \sec (c+d x))^{3/2}}-\frac{\int \frac{\cos (c+d x) \left (\frac{1}{2} (7 A b-4 a B)-a A \sec (c+d x)-\frac{5}{2} A b \sec ^2(c+d x)\right )}{(a+b \sec (c+d x))^{5/2}} \, dx}{2 a}\\ &=-\frac{(7 A b-4 a B) \sin (c+d x)}{4 a^2 d (a+b \sec (c+d x))^{3/2}}+\frac{A \cos (c+d x) \sin (c+d x)}{2 a d (a+b \sec (c+d x))^{3/2}}+\frac{\int \frac{\frac{1}{4} \left (4 a^2 A+35 A b^2-20 a b B\right )+\frac{5}{2} a A b \sec (c+d x)-\frac{3}{4} b (7 A b-4 a B) \sec ^2(c+d x)}{(a+b \sec (c+d x))^{5/2}} \, dx}{2 a^2}\\ &=-\frac{(7 A b-4 a B) \sin (c+d x)}{4 a^2 d (a+b \sec (c+d x))^{3/2}}+\frac{A \cos (c+d x) \sin (c+d x)}{2 a d (a+b \sec (c+d x))^{3/2}}-\frac{b \left (27 a^2 A b-35 A b^3-12 a^3 B+20 a b^2 B\right ) \tan (c+d x)}{12 a^3 \left (a^2-b^2\right ) d (a+b \sec (c+d x))^{3/2}}-\frac{\int \frac{-\frac{3}{8} \left (a^2-b^2\right ) \left (4 a^2 A+35 A b^2-20 a b B\right )-\frac{3}{4} a b \left (3 a^2 A-7 A b^2+4 a b B\right ) \sec (c+d x)+\frac{1}{8} b \left (27 a^2 A b-35 A b^3-12 a^3 B+20 a b^2 B\right ) \sec ^2(c+d x)}{(a+b \sec (c+d x))^{3/2}} \, dx}{3 a^3 \left (a^2-b^2\right )}\\ &=-\frac{(7 A b-4 a B) \sin (c+d x)}{4 a^2 d (a+b \sec (c+d x))^{3/2}}+\frac{A \cos (c+d x) \sin (c+d x)}{2 a d (a+b \sec (c+d x))^{3/2}}-\frac{b \left (27 a^2 A b-35 A b^3-12 a^3 B+20 a b^2 B\right ) \tan (c+d x)}{12 a^3 \left (a^2-b^2\right ) d (a+b \sec (c+d x))^{3/2}}-\frac{b \left (33 a^4 A b-170 a^2 A b^3+105 A b^5-12 a^5 B+104 a^3 b^2 B-60 a b^4 B\right ) \tan (c+d x)}{12 a^4 \left (a^2-b^2\right )^2 d \sqrt{a+b \sec (c+d x)}}+\frac{2 \int \frac{\frac{3}{16} \left (a^2-b^2\right )^2 \left (4 a^2 A+35 A b^2-20 a b B\right )+\frac{1}{8} a b \left (3 a^4 A-54 a^2 A b^2+35 A b^4+36 a^3 b B-20 a b^3 B\right ) \sec (c+d x)+\frac{1}{16} b \left (33 a^4 A b-170 a^2 A b^3+105 A b^5-12 a^5 B+104 a^3 b^2 B-60 a b^4 B\right ) \sec ^2(c+d x)}{\sqrt{a+b \sec (c+d x)}} \, dx}{3 a^4 \left (a^2-b^2\right )^2}\\ &=-\frac{(7 A b-4 a B) \sin (c+d x)}{4 a^2 d (a+b \sec (c+d x))^{3/2}}+\frac{A \cos (c+d x) \sin (c+d x)}{2 a d (a+b \sec (c+d x))^{3/2}}-\frac{b \left (27 a^2 A b-35 A b^3-12 a^3 B+20 a b^2 B\right ) \tan (c+d x)}{12 a^3 \left (a^2-b^2\right ) d (a+b \sec (c+d x))^{3/2}}-\frac{b \left (33 a^4 A b-170 a^2 A b^3+105 A b^5-12 a^5 B+104 a^3 b^2 B-60 a b^4 B\right ) \tan (c+d x)}{12 a^4 \left (a^2-b^2\right )^2 d \sqrt{a+b \sec (c+d x)}}+\frac{2 \int \frac{\frac{3}{16} \left (a^2-b^2\right )^2 \left (4 a^2 A+35 A b^2-20 a b B\right )+\left (\frac{1}{8} a b \left (3 a^4 A-54 a^2 A b^2+35 A b^4+36 a^3 b B-20 a b^3 B\right )-\frac{1}{16} b \left (33 a^4 A b-170 a^2 A b^3+105 A b^5-12 a^5 B+104 a^3 b^2 B-60 a b^4 B\right )\right ) \sec (c+d x)}{\sqrt{a+b \sec (c+d x)}} \, dx}{3 a^4 \left (a^2-b^2\right )^2}+\frac{\left (b \left (33 a^4 A b-170 a^2 A b^3+105 A b^5-12 a^5 B+104 a^3 b^2 B-60 a b^4 B\right )\right ) \int \frac{\sec (c+d x) (1+\sec (c+d x))}{\sqrt{a+b \sec (c+d x)}} \, dx}{24 a^4 \left (a^2-b^2\right )^2}\\ &=-\frac{\left (33 a^4 A b-170 a^2 A b^3+105 A b^5-12 a^5 B+104 a^3 b^2 B-60 a b^4 B\right ) \cot (c+d x) E\left (\sin ^{-1}\left (\frac{\sqrt{a+b \sec (c+d x)}}{\sqrt{a+b}}\right )|\frac{a+b}{a-b}\right ) \sqrt{\frac{b (1-\sec (c+d x))}{a+b}} \sqrt{-\frac{b (1+\sec (c+d x))}{a-b}}}{12 a^4 (a-b) b (a+b)^{3/2} d}-\frac{(7 A b-4 a B) \sin (c+d x)}{4 a^2 d (a+b \sec (c+d x))^{3/2}}+\frac{A \cos (c+d x) \sin (c+d x)}{2 a d (a+b \sec (c+d x))^{3/2}}-\frac{b \left (27 a^2 A b-35 A b^3-12 a^3 B+20 a b^2 B\right ) \tan (c+d x)}{12 a^3 \left (a^2-b^2\right ) d (a+b \sec (c+d x))^{3/2}}-\frac{b \left (33 a^4 A b-170 a^2 A b^3+105 A b^5-12 a^5 B+104 a^3 b^2 B-60 a b^4 B\right ) \tan (c+d x)}{12 a^4 \left (a^2-b^2\right )^2 d \sqrt{a+b \sec (c+d x)}}+\frac{\left (4 a^2 A+35 A b^2-20 a b B\right ) \int \frac{1}{\sqrt{a+b \sec (c+d x)}} \, dx}{8 a^4}+\frac{\left (b \left (105 A b^4+5 a b^3 (7 A-12 B)+6 a^4 (A+2 B)-5 a^2 b^2 (27 A+4 B)-a^3 (27 A b-84 b B)\right )\right ) \int \frac{\sec (c+d x)}{\sqrt{a+b \sec (c+d x)}} \, dx}{24 a^4 (a-b) (a+b)^2}\\ &=-\frac{\left (33 a^4 A b-170 a^2 A b^3+105 A b^5-12 a^5 B+104 a^3 b^2 B-60 a b^4 B\right ) \cot (c+d x) E\left (\sin ^{-1}\left (\frac{\sqrt{a+b \sec (c+d x)}}{\sqrt{a+b}}\right )|\frac{a+b}{a-b}\right ) \sqrt{\frac{b (1-\sec (c+d x))}{a+b}} \sqrt{-\frac{b (1+\sec (c+d x))}{a-b}}}{12 a^4 (a-b) b (a+b)^{3/2} d}+\frac{\left (105 A b^4+5 a b^3 (7 A-12 B)+6 a^4 (A+2 B)-5 a^2 b^2 (27 A+4 B)-a^3 (27 A b-84 b B)\right ) \cot (c+d x) F\left (\sin ^{-1}\left (\frac{\sqrt{a+b \sec (c+d x)}}{\sqrt{a+b}}\right )|\frac{a+b}{a-b}\right ) \sqrt{\frac{b (1-\sec (c+d x))}{a+b}} \sqrt{-\frac{b (1+\sec (c+d x))}{a-b}}}{12 a^4 (a-b) (a+b)^{3/2} d}-\frac{\sqrt{a+b} \left (4 a^2 A+35 A b^2-20 a b B\right ) \cot (c+d x) \Pi \left (\frac{a+b}{a};\sin ^{-1}\left (\frac{\sqrt{a+b \sec (c+d x)}}{\sqrt{a+b}}\right )|\frac{a+b}{a-b}\right ) \sqrt{\frac{b (1-\sec (c+d x))}{a+b}} \sqrt{-\frac{b (1+\sec (c+d x))}{a-b}}}{4 a^5 d}-\frac{(7 A b-4 a B) \sin (c+d x)}{4 a^2 d (a+b \sec (c+d x))^{3/2}}+\frac{A \cos (c+d x) \sin (c+d x)}{2 a d (a+b \sec (c+d x))^{3/2}}-\frac{b \left (27 a^2 A b-35 A b^3-12 a^3 B+20 a b^2 B\right ) \tan (c+d x)}{12 a^3 \left (a^2-b^2\right ) d (a+b \sec (c+d x))^{3/2}}-\frac{b \left (33 a^4 A b-170 a^2 A b^3+105 A b^5-12 a^5 B+104 a^3 b^2 B-60 a b^4 B\right ) \tan (c+d x)}{12 a^4 \left (a^2-b^2\right )^2 d \sqrt{a+b \sec (c+d x)}}\\ \end{align*}
Mathematica [A] time = 14.7169, size = 823, normalized size = 1.2 \[ \frac{(b+a \cos (c+d x))^3 \sec ^3(c+d x) \left (\frac{2 \left (10 B a^3-13 A b a^2-6 b^2 B a+9 A b^3\right ) \sin (c+d x) b^2}{3 a^4 \left (b^2-a^2\right )^2}-\frac{2 \left (A b^5 \sin (c+d x)-a b^4 B \sin (c+d x)\right )}{3 a^4 \left (a^2-b^2\right ) (b+a \cos (c+d x))^2}-\frac{2 \left (10 A \sin (c+d x) b^6-7 a B \sin (c+d x) b^5-14 a^2 A \sin (c+d x) b^4+11 a^3 B \sin (c+d x) b^3\right )}{3 a^4 \left (a^2-b^2\right )^2 (b+a \cos (c+d x))}+\frac{A \sin (2 (c+d x))}{4 a^3}\right )}{d (a+b \sec (c+d x))^{5/2}}-\frac{(b+a \cos (c+d x))^2 \sec (c+d x) \left (-a (a+b) \left (12 B a^5-33 A b a^4-104 b^2 B a^3+170 A b^3 a^2+60 b^4 B a-105 A b^5\right ) E\left (\sin ^{-1}\left (\tan \left (\frac{1}{2} (c+d x)\right )\right )|\frac{a-b}{a+b}\right ) \sqrt{\frac{(b+a \cos (c+d x)) \sec ^2\left (\frac{1}{2} (c+d x)\right )}{a+b}} \sec ^2\left (\frac{1}{2} (c+d x)\right )+b (a+b) \left (6 (A+2 B) a^5-3 b (13 A+48 B) a^4+4 b^2 (57 A+10 B) a^3+2 b^3 (60 B-29 A) a^2-30 b^4 (7 A+2 B) a+105 A b^5\right ) \text{EllipticF}\left (\sin ^{-1}\left (\tan \left (\frac{1}{2} (c+d x)\right )\right ),\frac{a-b}{a+b}\right ) \sqrt{\frac{(b+a \cos (c+d x)) \sec ^2\left (\frac{1}{2} (c+d x)\right )}{a+b}} \sec ^2\left (\frac{1}{2} (c+d x)\right )+3 (a-b)^2 (a+b)^2 \left (4 A a^2-20 b B a+35 A b^2\right ) \left ((a-b) \text{EllipticF}\left (\sin ^{-1}\left (\tan \left (\frac{1}{2} (c+d x)\right )\right ),\frac{a-b}{a+b}\right )+2 a \Pi \left (-1;-\sin ^{-1}\left (\tan \left (\frac{1}{2} (c+d x)\right )\right )|\frac{a-b}{a+b}\right )\right ) \sqrt{\frac{(b+a \cos (c+d x)) \sec ^2\left (\frac{1}{2} (c+d x)\right )}{a+b}} \sec ^2\left (\frac{1}{2} (c+d x)\right )-a \left (12 B a^5-33 A b a^4-104 b^2 B a^3+170 A b^3 a^2+60 b^4 B a-105 A b^5\right ) (b+a \cos (c+d x)) \left (\cos (c+d x) \sec ^2\left (\frac{1}{2} (c+d x)\right )\right )^{3/2} \sec (c+d x) \tan \left (\frac{1}{2} (c+d x)\right )\right )}{12 a^5 \left (a^2-b^2\right )^2 d \left (\cos (c+d x) \sec ^2\left (\frac{1}{2} (c+d x)\right )\right )^{3/2} (a+b \sec (c+d x))^{5/2}} \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 0.957, size = 10322, normalized size = 15.1 \begin{align*} \text{output too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B \sec \left (d x + c\right ) + A\right )} \cos \left (d x + c\right )^{2}}{{\left (b \sec \left (d x + c\right ) + a\right )}^{\frac{5}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (B \cos \left (d x + c\right )^{2} \sec \left (d x + c\right ) + A \cos \left (d x + c\right )^{2}\right )} \sqrt{b \sec \left (d x + c\right ) + a}}{b^{3} \sec \left (d x + c\right )^{3} + 3 \, a b^{2} \sec \left (d x + c\right )^{2} + 3 \, a^{2} b \sec \left (d x + c\right ) + a^{3}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B \sec \left (d x + c\right ) + A\right )} \cos \left (d x + c\right )^{2}}{{\left (b \sec \left (d x + c\right ) + a\right )}^{\frac{5}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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